通过变量获取位置，然后在mongodb中修改特定对象 [英] Get position with variable and then modify specific object in mongodb

问题描述

如何使该查询使用我的变量而不是硬编码0?

How can I make this query use my variable instead of the hard coded 0?

let pos = 0;

{$set: {'answers.0.acknowledged': data}}

推荐答案

通常，您的选择是模板文字，

Usually you choices are template literals, Array.join, String.concat etc:

let pos = 0;
let data = 'data';

let query = {$set: {[['answers.', pos,'.acknowledged'].join('')]: data}}

console.log(query);

使用 String.concat :

let pos = 0;
let data = 'data';
let query = {$set: {['answers.'.concat(pos,'.acknowledged')]: data}}
console.log(query);

Array.join ， String.concat 具有更好的浏览器支持，其中模板文字可以不是.如果要在客户端使用它们.如果您在后端使用它们，则可能不必担心.

Array.join, String.concat has a much better browsers support where template literals do not. If they were to be used @ the client side. In your case if you are using them at the back end you probably have nothing to worry about.

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