通过组数获取$ group结果 [英] Obtaining $group result with group count

问题描述

假设我有一个名为"posts"的集合(实际上这是一个更复杂的集合，posts太简单了)，结构如下:

Assuming I have a collection called "posts" (in reality it is a more complex collection, posts is too simple) with the following structure:

> db.posts.find()

{ "_id" : ObjectId("50ad8d451d41c8fc58000003"), "title" : "Lorem ipsum", "author" : 
"John Doe", "content" : "This is the content", "tags" : [ "SOME", "RANDOM", "TAGS" ] }

我希望这个集合跨越数十万个，甚至数百万个，我需要按标签查询帖子，并按标签对结果进行分组并显示分页的结果.这就是聚合框架的用处.我计划使用aggregate()方法来查询集合:

I expect this collection to span hundreds of thousands, perhaps millions, that I need to query for posts by tags and group the results by tag and display the results paginated. This is where the aggregation framework comes in. I plan to use the aggregate() method to query the collection:

db.posts.aggregate([
  { "$unwind" : "$tags" },
  { "$group" : {
      _id: { tag: "$tags" },
      count: { $sum: 1 }
  } }
]);

要注意的是，要创建分页器，我需要知道输出数组的长度.我知道可以做到这一点:

The catch is that to create the paginator I would need to know the length of the output array. I know that to do that you can do:

db.posts.aggregate([
  { "$unwind" : "$tags" },
  { "$group" : {
      _id: { tag: "$tags" },
      count: { $sum: 1 }
  } }
  { "$group" : {
      _id: null,
      total: { $sum: 1 }
  } }
]);

但是这将丢弃先前管道(第一组)的输出.在保留每个管道的输出的同时，有两种方法可以合并在一起的方法吗?我知道可以将整个聚合操作的输出转换为某种语言的数组，并对内容进行计数，但是管道输出可能会超过16Mb的限制.另外，仅仅为了获得计数而执行相同的查询似乎是一种浪费.

But that would discard the output from previous pipeline (the first group). Is there a way that the two operations be combined while preserving each pipeline's output? I know that the output of the whole aggregate operation can be cast to an array in some language and have the contents counted but there may be a possibility that the pipeline output may exceed the 16Mb limit. Also, performing the same query just to obtain the count seems like a waste.

那么可以同时获得文件结果并计数吗?感谢您的帮助.

So is obtaining the document result and count at the same time possible? Any help is appreciated.

推荐答案

1. 使用$project将tag和count保存到tmp
2. 使用$push或addToSet将tmp存储到您的data列表中.

1. Use $project to save tag and count into tmp
2. Use $push or addToSet to store tmp into your data list.

代码:

db.test.aggregate(
    {$unwind: '$tags'}, 
    {$group:{_id: '$tags', count:{$sum:1}}},
    {$project:{tmp:{tag:'$_id', count:'$count'}}}, 
    {$group:{_id:null, total:{$sum:1}, data:{$addToSet:'$tmp'}}}
)

输出:

{
    "result" : [
            {
                    "_id" : null,
                    "total" : 5,
                    "data" : [
                            {
                                    "tag" : "SOME",
                                    "count" : 1
                            },
                            {
                                    "tag" : "RANDOM",
                                    "count" : 2
                            },
                            {
                                    "tag" : "TAGS1",
                                    "count" : 1
                            },
                            {
                                    "tag" : "TAGS",
                                    "count" : 1
                            },
                            {
                                    "tag" : "SOME1",
                                    "count" : 1
                            }
                      ]
              }
      ],
      "ok" : 1
}

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