MongoDB聚合查询以对累积值进行减法和分组 [英] Mongodb aggregation query to subtract and grouping of cumulative value

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本文介绍了MongoDB聚合查询以对累积值进行减法和分组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

{
"_id" : ObjectId("58f5a22d22679039176d2ee8"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:01:01.000+05:30"), 
"Utilization" : NumberInt("63654480"),
"RunStatus" : NumberInt("1"),   
"ProductsCount" : NumberInt("681350")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2ee9"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:02:02.000+05:30"), 
"Utilization" : NumberInt("63655480"),
"RunStatus" : NumberInt("1"),   
"ProductsCount" : NumberInt("681370")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2eea"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:03:02.000+05:30"), 
"Utilization" : NumberInt("63656480"),
"RunStatus" : NumberInt("0"),   
"ProductsCount" : NumberInt("681390")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2eeb"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:04:02.000+05:30"), 
"Utilization" : NumberInt("63657480"),
"RunStatus" : NumberInt("1"),   
"ProductsCount" : NumberInt("681420")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2eec"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:05:02.000+05:30"), 
"Utilization" : NumberInt("63658480"),
"RunStatus" : NumberInt("1"),   
"ProductsCount" : NumberInt("681450"),  
},
{
"_id" : ObjectId("58f5a22d22679039176d2eed"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:06:02.000+05:30"), 
"Utilization" : NumberInt("63659480"),
"RunStatus" : NumberInt("1"),   
"ProductsCount" : NumberInt("681470")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2eee"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:07:02.000+05:30"), 
"Utilization" : NumberInt("63659780"),
"RunStatus" : NumberInt("0"),   
"ProductsCount" : NumberInt("681490")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2eef"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:08:03.000+05:30"), 
"Utilization" : NumberInt("63659880"),
"RunStatus" : NumberInt("1"),   
"ProductsCount" : NumberInt("681525")   
},
{
"_id" : ObjectId("58f5a22d22679039176d2ef0"),
"MachineID" : NumberInt("1001"),
"Timestamp" : ISODate("2017-04-18T07:09:03.000+05:30"), 
"Utilization" : NumberInt("63659980"),
"RunStatus" : ("0"),
"ProductsCount" : NumberInt("681563")
}

在上面的集合中,利用率 ProductsCount 是累积值,并随时间增加.

From the above collection, Utilization and ProductsCount are cumulative values and incremental over time.

需要将当前行的 Utilization 减去下一行的 Utilization (按升序排列).以及基于 RunStatus ProductsCount 的相同操作.

Need to subtract Utilization of current row with Utilization of next row which is sorted in ascending order. As well as same operation for ProductsCount based on RunStatus.

如果当前行的 RunStatus 为1,下一行为0,则利用率 ProductsCount 之差应映射为下一行的RunStatus 为0.

If RunStatus of current row is 1 and next row is 0, then the difference in Utilization and ProductsCount should be mapped to RunStatus of next row which is 0.

然后根据 MachineID RunStatus

预期结果

/* 1 */
{   
"MachineID" : 1001,
"RunStatus" : 1,
"Utilization" : 4100,
"ProducedCount" : 135
},

/* 2 */
{   
"MachineID" : NumberInt("1001"),
"RunStatus" : NumberInt("0"),
"Utilization" : 1400,
"ProducedCount" : 78
}

结果在聚合框架中是必需的.请帮助.

这是我尝试过的,

db.collection.aggregate([
{ "$match" : { "$and" : [ { "MachineID" : { "$in" : [ 1001]}} , 
    { "Timestamp" : { "$gte" : ISODate("2017-04-18T01:30:00.000Z"), 
    "$lte" : ISODate("2017-04-19T01:30:00.000Z")}},]}
}, 
{
    "$addFields": {"lastUtilization": 0}
},
{
    "$addFields": {"lastProductsCount" : 0}
},
{
    "$group": {
        "_id": 
        {
             MachineID : '$MachineID',
            "RunStatus": "$RunStatus"
        },
        "Utilization" : 
        {
            "$sum" : 
            {
                "$cond": [
                        { "$ne": [ "$lastUtilization", 0 ] },
                         {"$subtract" : ["$Utilization", 
"$lastUtilization"]}, 0
                    ]
            }
        }, 
        "ProductsCount" : 
        {
            "$sum" : 
            {
                "$cond": [
                        { "$ne": [ "$lastProductsCount", 0 ] },
                         {"$subtract" : ["$ProductsCount", 
"$lastProductsCount"]}, 0
                    ]
            }
        }, 
        "lastProductsCount" : { "$avg" : "$ProductsCount"}, 
        "lastUtilization" : { "$avg" : "$Utilization"}
}
},
{
    "$project": 
    {
        "MachineID": "$_id.MachineID", 
        "RunStatus" : "$_id.RunStatus", 
        "Utilization" : "$Utilization", 
        "ProductsCount" : "$ProductsCount"
    }
},
]);

推荐答案

这是怎么回事?它不会计算小时数,但会执行其他所有操作.

How's this? It doesn't compute the hour, but it does everything else.

[
    {
      $match: {
          $and: [
              {MachineID: {$in: [1001]}},
              {
                Timestamp: {
                    $gte: ISODate("2017-04-18T01:30:00.000Z"),
                    $lte: ISODate("2017-04-19T01:30:00.000Z")
                }
              }
          ]
      }
    },
    // Add all data to one array.
    {$group: {_id: "$MachineID", all: {$push: "$$ROOT"}}},
    // Create an array of (element, array index) pairs.
    {$addFields: {allWithIndex: {$zip: {inputs: ["$all", {$range: [0, {$size: "$all"}]}]}}}},
    // Create an array of {current: <element>, previous: <previous element>} pairs.
    {
      $project: {
          pairs: {
              $map: {
                  input: "$allWithIndex",
                  in : {
                      current: {$arrayElemAt: ["$$this", 0]},
                      prev: {
                          $arrayElemAt: [
                              "$all",
                              // Set prev == current for the first element.
                              {$max: [0, {$subtract: [{$arrayElemAt: ["$$this", 1]}, 1]}]}
                          ]
                      }
                  }
              }
          }
      }
    },
    // Compute the deltas.
    {$unwind: "$pairs"},
    {
      $group: {
          _id: {MachineID: "$_id", RunStatus: "$pairs.current.RunStatus"},
          ProductsCount:
              {$sum: {$subtract: ["$pairs.current.ProductsCount", "$pairs.prev.ProductsCount"]}},
          Utilization:
              {$sum: {$subtract: ["$pairs.current.Utilization", "$pairs.prev.Utilization"]}},
      }
    }
]

这篇关于MongoDB聚合查询以对累积值进行减法和分组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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