在PHP上显示错误 [英] Display error on php

问题描述

//我已经更新了代码php并改善了问题

// I have updated my code php and improve my question

我有一个登录表单，当我输入错误密码时，我没有此错误:

i have a login form, and when i wrong password i don't have this error:

您尚未注册或密码错误！"

"your are not register or your password is wrong !"

我什么都没有，什么也没有出现.

I have nothing, there is nothing that appears.

这是我的代码php，我的数据是mongodb:

this is my code php, my data is mongodb :

<?php



if (isset($_POST['submit']) && $_POST['submit'] == "Login"){
    $username = strip_tags($_POST['username']);
    $password = strip_tags($_POST['password']);
    $error    = array();
    // Username Validation
    if (empty($username)) {
         $error[] = " <h2>  complete username </h2>";
    }
    if (empty($password)) {
         $error[] = " <h2> complete password</h2> ";
    }

        // connexion data
    if (count($error) == 0)
    {
        $host               = 'localhost';
        $database_name      = 'Projet';
        $database_user_name = '';
        $database_password  = '';
        $connection         = new MongoClient();

        if ($connection)
        {
            // select data
            $database = $connection->$database_name;

            // Select collection
            $collection = $database->reg_users;
            $user_data  = array(
                "username" => $username,
                "password" => md5($password)
            );
            $result     = $collection->find($user_data);
            if ($result>0)
            {
                header("Location: Articles.php");
                foreach ($result as $doc)
                 {
                    $_SESSION['email']    = $doc['email'];
                    $_SESSION['username'] = $doc['username'];
                 }

             }else{

                      $error[] = " <h2> your are not register or your password is wrong !  </h2>";
                }

            } else {
                      $error[] = " no mongodb connection";
                }
        }  

         if(count($error) > 0) 
        {
             foreach($error as $e)
             {
                echo $e;
             }
        }
}

推荐答案

isset将返回布尔结果，因此，如果要执行该代码块，则需要这样编写:

isset will return a boolean result and therefor needs to be written more like this if you want that code block to execute:

if (isset($_POST['submit']) && $_POST['submit'] == "Login")

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