如何使用不变的Salat案例类更新Mongo中的对象 [英] How to update object in Mongo with an immutable Salat case class

查看:89
本文介绍了如何使用不变的Salat案例类更新Mongo中的对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在与Scala,Salat,Casbah,Mongo,Play2,BackboneJS进行一个项目...但是同时要学习很多新东西...我对Scala没问题,但是我发现我的代码糟糕透顶,我真的不知道有什么解决方案可以改善它.

I'm working on a project with Scala, Salat, Casbah, Mongo, Play2, BackboneJS... But it's quite a lot of new things to learn in the same time... I'm ok with Scala but I find my code crappy and I don't really know what's the solution to improve it.

基本上我的用例是:

  • Play2将MongoDB对象发送到浏览器的JS代码
  • JS代码(通过Backbone模型)更新对象数据
  • JS将更新后的JSON发送回服务器(通过Backbone保存方法发送,并由Play使用json bodyparser接收)
  • Play收到的JSON应该更新MongoDB中的对象
  • 出于安全原因(对象ID,creationDate ...),某些字段不可更新

我的问题是最后一部分. 我使用带有Salat的案例类来表示存储在MongoDB中的对象.

My problem is the last part. I'm using case classes with Salat as a representation of the objects stored in MongoDB.

我真的不知道如何处理从JS代码收到的JSON.

I don't really know how to handle the JSON i receive from the JS code.

  • 我应该将JSON绑定到Salat案例类中,然后要求Mongo用完整的新case类对象覆盖以前的对象数据吗? 如果是这样,Play2或Salat是否可以根据接收到的JSON自动创建案例类?

  • Should I bind the JSON into the Salat case class and then ask Mongo to override the previous object data by the full new case class object? If so is there a way with Play2 or Salat to automatically create back the case class from the received JSON?

我应该用$ set分别处理我要更新的字段的JSON字段吗?

Should I handle my JSON fields individually with $set for the fields I want to update?

我应该使案例类的元素可变吗?例如,这实际上是我们在Java中使用Hibernate进行的操作:从DB中获取对象,更改其状态并保存.但这似乎不是使用Scala的合适方法...

Should i make the elements of my case class mutable? It's what we actually do in Java with Hibernate for exemple: get the object from DB, change its state, and save it. But it doesn't seem to be the appropriate way to do with Scala...

如果有人可以给我一些关于我的用例的建议,那会很好,因为我真的不知道该怎么办:(

If someone can give me some advices for my usecase it would be nice because I really don't know what to do :(

我在这里提出了一个相关问题:我应该用不可变或可变的数据结构表示数据库数据吗?

I asked a related question here: Should I represent database data with immutable or mutable data structures?

推荐答案

Salat使用lift-json处理JSON-请参见

Salat handles JSON using lift-json - see https://github.com/novus/salat/wiki/SalatWithPlay2.

Play本身使用Jerkson,这是解码模型对象的另一种方法-请参见 http://blog.xebia.com/2012/07/22/play-body-parsing-with-jerkson/.

Play itself uses Jerkson, which is another way to decode your model objects - see http://blog.xebia.com/2012/07/22/play-body-parsing-with-jerkson/ for an example.

可以免费制作一个示例Github项目示例,以演示您的问题并发布到Salat邮件列表中,网址为 https://groups.google.com/group/scala-salat 以获得帮助.

Feel free to make a small sample Github project that demonstrates your issue and post to the Salat mailing list at https://groups.google.com/group/scala-salat for help.

这篇关于如何使用不变的Salat案例类更新Mongo中的对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆