比较同一文档中的两个数组字段 [英] Compare two array fields in same document
本文介绍了比较同一文档中的两个数组字段的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有两个带有数据的不同数组,我必须将两个对象中的两个数组合并到一个对象中,如何在MongoDB Aggregation的帮助下进行合并. 这是我的两个数组
I have two different Arrays with Data and I have to merge two arrays same object in one object how can I merge with help of MongoDB Aggregation. here are my two Arrays
{"ids" : [
{
"_id" : ObjectId("5ba8d8dfaa988532967029af"),
"level" : 2,
"completed" : 5,
"asset" : ObjectId("5ba8caa1aa98853296702989")
},
{
"_id" : ObjectId("5ba8d8dfaa988532967029b0"),
"level" : 2,
"completed" : 3,
"asset" : ObjectId("5ba8caf6aa9885329670298a")
},
{
"_id" : ObjectId("5ba8d8dfaa988532967029b1"),
"level" : 2,
"asset" : ObjectId("5ba8cb09aa9885329670298b")
}]}
{"total" : [
{
"total" : 1,
"asset" : ObjectId("5ba8caa1aa98853296702989"),
"level" : 2
},
{
"total" : 1,
"asset" : ObjectId("5ba8caf6aa9885329670298a"),
"level" : 2
},
{
"total" : 1,
"asset" : ObjectId("5ba8cb09aa9885329670298b"),
"level" : 2
}]}
在上面的两个数组中显示了数据,我只想合并资产和级别相同的那个对象
in upper two arrays data are shown I want to merge only that object whose asset and level are same
Expected Result:[{
"level" : 2,
"asset" : ObjectId("5ba8caa1aa98853296702989"),
"total" : 1,
"completed" : 5,
},{
"level" : 2,
"asset" : ObjectId("5ba8caf6aa9885329670298a"),
"total" : 1,
"completed" : 3,
}]
推荐答案
如果已经有两个对象,则可以这样做.但是如果您需要从mongoDb中获取它,则应该在mongo聚合中使用$ mergeObject.
if you already have two objects then you can do like this. but if you need to get it from mongoDb then you should use $mergeObject in mongo aggregation.
var a = [
{
"_id" : "5ba8d8dfaa988532967029af",
"level" : 2,
"completed" : 5,
"asset" : "5ba8caa1aa98853296702989"
},
{
"_id" : "5ba8d8dfaa988532967029b0",
"level" : 2,
"completed" : 3,
"asset" : "5ba8caf6aa9885329670298a"
}];
var b = [
{
"total" : 1,
"asset" : "5ba8caa1aa98853296702989",
"level" : 2
},
{
"total" : 1,
"asset" : "5ba8caf6aa9885329670298a",
"level" : 2
}];
var output = [];
function extend(obj, src) {
src.forEach(function(key,index) {
if(obj[index]["asset"] == src[index]["asset"] && obj[index]["level"] == src[index]["level"]){
let c = {...obj[index],...src[index]};
output.push(c);
}
});
}
extend(a, b);
console.log(output)
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