根据精益查询的结果创建猫鼬模型 [英] Create mongoose model from results of lean query

问题描述

我正在使用精益查询来更快地从数据库中检索大型数据集.检索到的大多数数据都是使用的，但未修改或保存，因此精益查询很好，但是我需要使用架构方法来修改和保存一小部分对象.

I am using a lean query to retrieve a large dataset from my database more quickly. Most of the data retrieved is used but not modified or saved, so the lean query is fine, but I need to modify and save a small proportion of the objects using the schema methods.

在遍历精益查询的结果时是否可以为这些结果创建猫鼬对象，而大多数结果都以精益格式保留?

Is it possible to create the mongoose objects for these results as I iterate through the results of my lean query, leaving the majority of the results in the lean format?

我知道的唯一方法是使用数据创建新对象，然后将isNew设置为false，但这需要我为此目的构造一个构造函数，而且似乎有些怪异.所以我想知道toObject()

The only way I know of is to create new objects using the data, then set isNew to false, but this requires me to make a constructor for this purpose and seems a bit hacky. So I was wondering if there's basically an opposite to toObject()

推荐答案

您可以使用 Model.hydrate() .

You can use Model.hydrate() for this.

这篇关于根据精益查询的结果创建猫鼬模型的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！