MongoDB where子句 [英] MongoDB where clause

问题描述

我有JSON格式的mongoDB"users"集合，我想返回所有具有保密性的数据.我该怎么办?

I have mongoDB "users" collection in JSON format and I want to return all the data having privacy is true. How can I do it ?

{

    "name" : "Maria Kari",
    "social" : [
        {
            "facebook" : "www.fb.com/maria.mongodb",
            "privacy" : true
        },
        {
            "twitter" : "www.tw.com/mongodb",
            "privacy" : false
        }
    ],
    "personal" : [
        {
            "cell_no" : "[phone]",
            "privacy" : true
        },
        {
            "email" : "[e-mail]",
            "privacy" : false
        }
    ]
}

在这里，我想返回具有隐私权的数据.例如，facebook，它具有的隐私等于true.如何为此建立查询?

Here, I want to return the data having privacy is true. For example, facebook, it has privacy is equal to true. How to build query for this ?

谢谢. :')

推荐答案

db.users.find( { 
    $or:[{ 'social.privacy': true },{'personal.privacy': true}] 
)

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