从猫鼬的"toJSON"支持中删除一个属性 [英] remove one property from mongoose 'toJSON' support

问题描述

我正在使用猫鼬的toJSON支持，如下所示:

I am using mongoose's toJSON support as below:

userSchema.set('toJSON', { getters: true, virtuals: true, minimize: false })

现在在猫鼬对象的toJSON()方法调用的返回结果中，我想删除某些敏感字段.该怎么做?

now in the returned result from a mongoose object's toJSON() method call, I want to remove certain sensitive fields. How to do that?

以不同的方式解释问题:

In different way to explain the issue:

某些字段，例如密码"，令牌"，我们只需要在查询中使用，而在返回结果中则不需要，如何隐藏它们以防各种查询返回?

Some certain fields like 'password', 'token' which we would need only in query, but not in returned result, how to hide them from returning from all kind of queries?

更新:这最终是我最终得到的，并且像魅力一样工作:

Update: This finally what I ended up with and working like a charm:

userSchema.options.toJSON = {
    getters: true,
    virtuals: true,
    minimize: false,
    transform: function (doc, ret, options) {
      delete ret.password
      delete ret.authToken
      return ret
    }
  }

推荐答案

您可以像这样自定义toJSON在您的架构上的工作方式:

you can customize how toJSON works on your schema like this:

/**
  * adjust toJSON transformation
  */ 
mySchema.options.toJSON = {
    transform: function(doc, ret, options) {
        ret.id = ret._id;
        delete ret.password;
        delete ret.token;
        delete ret._id;
        delete ret.__v;
        return ret;
    }
};

doc是要序列化的文档，ret是将转换为JSON的普通JS对象.然后，您可以根据需要操作ret.

doc is the document to be serialized, ret is the plain JS object that will be transformed into JSON. You may then manipulate ret however you want.

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