从集合管道中的集合中减去子文档 [英] Subtract subdocuments from collection in aggregate pipeline

问题描述

我正在尝试从mongodb中检索文档，并根据条件(deleted != null)从数组中删除一些对象.这是我定位的商品的简化示例:

I'm trying to retrieve a document from a mongodb and remove some objects from an array based on a condition (deleted != null). Here is a simplified example of the item I'm targeting:

{
    "_id" : ObjectId("54ec9cac83a214491d2110f4"),
    "name" : "my_images", 
    "images" : [
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2311026b0cb289ed04188"),
            "deleted" : null,
            "date_added" : ISODate("2015-02-28T21:20:16.961Z"),
        },
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2314a26b0cb289ed04189"),
            "deleted" : ISODate("2015-02-24T15:38:14.826Z"),
            "date_added" : ISODate("2015-02-28T21:21:14.910Z"),
        },
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2315526b0cb289ed0418a"),
            "deleted" : null,
            "date_added" : ISODate("2015-02-28T21:21:25.042Z"),
        },
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2315d26b0cb289ed0418b"),
            "deleted" : null,
            "date_added" : ISODate("2015-02-28T21:21:33.081Z"),
        }
    ]
}

成功的查询将返回相同的内容，但是其中一个图像对象已删除，因为它具有ISODate而不是null.像这样:

The successful query will return the same but with one of the image objects removed as it has an ISODate rather than null. Like this:

{
    "_id" : ObjectId("54ec9cac83a214491d2110f4"),
    "name" : "my_images", 
    "images" : [
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2311026b0cb289ed04188"),
            "deleted" : null,
            "date_added" : ISODate("2015-02-28T21:20:16.961Z"),
        },
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2315526b0cb289ed0418a"),
            "deleted" : null,
            "date_added" : ISODate("2015-02-28T21:21:25.042Z"),
        },
        {
            "ext" : "jpeg",
            "type" : "image/jpeg",
            "_id" : ObjectId("54f2315d26b0cb289ed0418b"),
            "deleted" : null,
            "date_added" : ISODate("2015-02-28T21:21:33.081Z"),
        }
    ]
}

我曾尝试使用聚集将图像复制到$unwind，然后仅将相关图像复制到$match，但是现在我需要重新创建文档，否则它将返回剩余的3个未缠绕"文档.

I have tried using aggregate to $unwind the images then $match only the relevant images but I now need to recreate the document other wise it returns the remaining 3 'unwound' documents.

这是我到目前为止的位置:

Here is where I am so far:

Collection.aggregate([
        { $match:
            { _id: ObjectID(collection_id) }
        },
        { $unwind: "$images" },
        { $match:
            { "images.deleted": null }
        }

        // Next step in the pipeline to
        // reconfigure into one document
        // goes here

    ], function (err, result) {
    if (err) {
        console.log(err);
        return;
    }
    console.log(result);
});

是否有一种方法可以从剩余的内容中创建一个文档，还是我会以完全错误的方式来解决这个问题?

Is there a way to create one document from what remains or am I going about this in entirely the wrong way?

谢谢.

推荐答案

正如您提到的那样，您需要将展开，过滤后的文档重新分组为原始形状.您可以使用$group:

As you alluded to, you need to re-group the unwound, filtered docs back into their original shape. You can do this with $group:

Collection.aggregate([
        { $match:
            { _id: ObjectID(collection_id) }
        },
        { $unwind: "$images" },
        { $match:
            { "images.deleted": null }
        },

        // Regroup the docs by _id to reassemble the images array
        {$group: {
            _id: '$_id',
            name: {$first: '$name'},
            images: {$push: '$images'}
        }}

    ], function (err, result) {
    if (err) {
        console.log(err);
        return;
    }
    console.log(result);
});

这篇关于从集合管道中的集合中减去子文档的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！