我不能让一个startService从我的广播接收器工作 [英] I can't get a startService working from my BroadcastReceiver

问题描述

我想，当警报会从我的广播接收器触发启动我的服务。我没有得到任何错误和code运行，但它不是我的启动服务，我没有得到任何错误。难道说是我的服务，或在清单有问题？

我注意到，我经常得到的问题，当谈到意图和语境。我试图读了它，但我不能找到一个网站，解释它的一个好办法，但。有什么建议？

 公共类报警扩展广播接收器{    @覆盖
    公共无效的onReceive（上下文的背景下，意图意图）{        振动器振动=（振动器）context.getSystemService（Context.VIBRATOR_SERVICE）;
        vibrator.vibrate（1000）;        意图为myService =新意图（BackgroundService.class.getName（））;
        context.startService（为myService）;
    }
}
 

****************** 清单*******

 ＆LT;服务机器人。BackgroundServiceNAME =机器人：工艺=：远程＆GT;
    ＆所述;意图滤光器＆gt;
    ＆lt;作用机器人：名字=se.davidsebela.ShutMeUp.BackgroundService/＆GT;
    ＆所述; /意图滤光器＆gt;
＆LT; /服务＆GT;＆lt;接收安卓过程=：遥控机器人：名字=报警＆GT;＆LT; /接收器＆GT;
＆LT; /用途＆gt;
 

解决方案

 意图为myService =新意图（BackgroundService.class.getName（））;
 

这将创建只是一个动作一个新的意图。的动作是BackgroundService类的名称。当您使用此将无法正常工作 startService（）。

而使用的意图构造，获取类和上下文参数，而不是：

 意图为myService =新意图（背景下，BackgroundService.class）;
 

I am trying to start my Service when an alarm gets triggered from my BroadcastReceiver. I am not getting any error and the code runs, but its not starting my service and I am not getting any errors. Could it be a problem that is in my Service or in the manifest?

I have noticed that I am often getting problems when it comes to Intents and Contexts. I have tried to read up on it, but I can't find a site that explains it in a good way though. Any suggestions?

public class Alarm extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {

        Vibrator vibrator = (Vibrator) context.getSystemService(Context.VIBRATOR_SERVICE);
        vibrator.vibrate(1000);

        Intent myService = new Intent(BackgroundService.class.getName());
        context.startService(myService); 
    }
}

****************** Manifest*******

<service android:name=".BackgroundService" android:process=":remote">
    <intent-filter>
    <action android:name="se.davidsebela.ShutMeUp.BackgroundService" />
    </intent-filter>
</service>

<receiver  android:process=":remote" android:name="Alarm"></receiver>
</application>

解决方案

Intent myService = new Intent(BackgroundService.class.getName());

This creates a new intent with just an action. The action is the name of the BackgroundService class. This won't work when you are using startService().

Rather use the intent constructor that gets a class and a context as arguments instead:

Intent myService = new Intent(context, BackgroundService.class);

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