从另一个线程以原子方式取消asio异步计时器 [英] Atomically cancel asio asynchronious timer from another thread
问题描述
我有一个定期运行的加速截止时间(例如 http://www.boost.org/doc/libs/1_35_0/doc/html/boost_asio/tutorial/tuttimer3/src.html ):
I have a boost deadline_timer which runs periodically (as in example http://www.boost.org/doc/libs/1_35_0/doc/html/boost_asio/tutorial/tuttimer3/src.html):
#include <iostream>
#include <boost/asio.hpp>
#include <boost/bind.hpp>
#include <boost/date_time/posix_time/posix_time.hpp>
void print(const boost::system::error_code& /*e*/,
boost::asio::deadline_timer* t)
{
t->expires_at(t->expires_at() + boost::posix_time::seconds(1));
t->async_wait(boost::bind(print,
boost::asio::placeholders::error, t, count));
}
int main()
{
boost::asio::io_service io;
boost::asio::deadline_timer t(io, boost::posix_time::seconds(1));
t.async_wait(boost::bind(print,
boost::asio::placeholders::error, &t));
io.run();
return 0;
}
现在我需要从另一个线程中取消它. 但是,如果取消调用仅在打印功能执行期间出现,而在expires_at调用之前出现,该怎么办?然后计时器将继续运行.
Now I need to cancel it from another thread. But what if the call of cancel appears just during print function execution but before expires_at call? Then timer will continue to run.
一种处理方法是运行类似的
One way to deal with it is to run something like
while (timer.cancel() == 0) {
}
在那个单独的线程函数中.
in that separate thread function.
但是也许有人知道可以更好地解决此问题?
But maybe somebody knows more elegant way this issue can be done?
推荐答案
实际上,这两种方法都不是很安全,只是因为deadline_timer
是
Actually, the both approaches are not quite safe, just because deadline_timer
is not thread-safe.
IMO,最简单和安全的方法是post
取消:
IMO, the most simple and safe way is to post
the cancellation:
//...
timer.get_io_service().post([&]{timer.cancel();})
//...
注意:在真实代码中,必须确保timer
超过函子(lambda).
NOTE: in the real code one has to ensure that timer
outlives the functor (lambda).
更新:如@sehe所述,此解决方案可能不起作用-因为当计时器不再等待时,取消处理程序可能出现在print
之前的io_service
队列中.
UPDATE: as @sehe mentioned, this solution might not work - because the cancelling handler may appear in the io_service
queue just before print
, when the timer is not waiting anymore.
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