输入不停止程序 [英] Input without stopping program

问题描述

我正在尝试制作一个倒计时计时器，打印剩余时间，当您输入内容时，它会打印您输入的内容.我的问题是我不想等待输入，只是继续运行计时器.我的错误代码:

I am trying to make a countdown timer that prints the time remaining, and when you input something, it prints what you inputted. My problem is I don't want to wait for the input, just keep running the timer. My incorrect code:

timer = 100
while True:
    print(timer)
    timer -= 1

    if input('> '):
        print('the output of input')

您可以说我想让计时器在后台打印时间.

You could say I want to have the timer printing the time in the background.

推荐答案

如果没有输入，这里的函数将超时:

Here's a function that will timeout if no input is given:

import select
import sys

def timeout_input(timeout, prompt="", timeout_value=None):
    sys.stdout.write(prompt)
    sys.stdout.flush()
    ready, _, _ = select.select([sys.stdin], [], [], timeout)
    if ready:
        return sys.stdin.readline().rstrip('\n')
    else:
        sys.stdout.write('\n')
        sys.stdout.flush()
        return timeout_value

您可以轻松地对其进行修改，以便通过将select.select上的超时值更改为1并循环timeout次来显示剩余时间.

You can easily modify it so it shows the remaining time by changing the timeout value on select.select to 1, and looping timeout times.

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