可捕获的致命错误:无法将类mysqli_result的对象转换为字符串 [英] Catchable fatal error: Object of class mysqli_result could not be converted to string

问题描述

试图获取我的第一个多表MySQL数据库，但是我发现一个错误，我只能把头弄乱了.在我将计算机扔出窗户之前，有人可以建议一种方法吗?

Trying to get my first multi-table MySQL database but i've gut an error I just can wrap my head around. Can someone please suggest an approach before I toss my computer out a window?

我有两个表:

1. 客户，其中具有以下行:* id，tourbk_id，tourstart，roomtype1，client_name *
2. tourprices ，其中包含以下行:* id，tour_id，tourstart，房间类型，房间价格*

1. clients which has rows: *id, tourbk_id, tourstart, roomtype1, client_name*
2. tourprices which has rows: *id, tour_id, tourstart, roomtype, roomprice*

目标

我打算在 clients 表中查找以下查询，以查询客户希望购买的游览，比较 client中的游览日期+游览名称+房间类型表，然后回显价格.

Goal

I'm intending for the following query to look, in the clients table for the tour the client wishes to purchase, compare the tour date + tour name + room type in the client table, and echo the price.

    $tourquery = "SELECT t.roomprice 
         FROM clients c, tourprices t 
         WHERE c.roomtype1 = t.roomtype 
         AND c.tourstart = t.tourstart
         AND c.tourbk_id = t.tour_id"; 
$tourresult = $db->query($tourquery); 

echo '<strong>',"Per room amount:  ",'</strong>'.$tourresult. "";

$tourresult->free();

照原样，结果只是一个错误，指出: 可捕获的致命错误:mysqli_result类的对象无法转换为字符串

As-is, the result is just an error stating: Catchable fatal error: Object of class mysqli_result could not be converted to string

非常感谢您的帮助.

推荐答案

query()函数返回资源，您需要从该函数返回的内容中获取一条记录.查看此页面上的示例，以了解如何从mysql打印数据

The query() function returns a resource, you'll want fetch a record from what's returned from that function. Look at the examples on this page to learn how to print data from mysql

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