mysqli_result类的对象无法转换为字符串 [英] Object of class mysqli_result could not be converted to string

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问题描述

我请Google帮我,我没有运气. :-( 这是生成错误的特定代码:

I asked Google to help me I got no luck. :-( Here's the particular code that generates the error:

$this->conn->query("UPDATE tz_members SET confirm='yes' WHERE usr='".$uname."'");

整个功能如下:

    function update_confirm_field($code) {

    $uname = $this->conn->query("SELECT usr FROM tz_members WHERE 
                     confirm='".$code."'");

    $this->conn->query("UPDATE tz_members SET confirm='yes' WHERE 
                     usr='".$uname."'");
}

如果我错过了一些愚蠢的事情,请原谅我.谁能告诉我是什么原因引起的??

Forgive me if I have missed something stupid. Can anyone tell me what's causing the problem please???

推荐答案

问题是$ uname是一个对象,而不是字符串.您需要调用$ uname的方法之一来访问数据.

The problem is that $uname is an object, not a string. You need to call one of $uname's methods to access the data.

    function update_confirm_field($code) {

    $uname = $this->conn->query("SELECT usr FROM tz_members WHERE 
                     confirm='".$code."'");

    while ($row = $uname->fetch_assoc()) { 

    $this->conn->query("UPDATE tz_members SET confirm='yes' WHERE 
                     usr='".$row["usr"]."'");

    }

}

应该执行的操作(或上述解决方案之一).

that should do it (or one of the above solutions).

这篇关于mysqli_result类的对象无法转换为字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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