根据查询将所有行提取到数组中 [英] Fetch all rows based on the query into an array

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本文介绍了根据查询将所有行提取到数组中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下代码:

  //--------------------------------------------------------------------------
  // 2) Query database for data
  //--------------------------------------------------------------------------
  $result = mysql_query("SELECT * FROM $tableName");          //query
  $array = mysql_fetch_row($result);                          //fetch result   

  //--------------------------------------------------------------------------
  // 3) echo result as json 
  //--------------------------------------------------------------------------
  echo json_encode($array);

我想做的是根据查询获取所有行并将其馈送到数组中,以提供如下输出:

What I would like to do is fetch all rows based on the query and feed those into the array, to give me an output like this:

["1", "", "", "", "", ""]
["2", "", "", "", "", ""]
etc...

我想我需要遍历行并建立数组,但我不知道如何.

I presume I need to loop through the rows and build up the array but I don't know how.

推荐答案

$result = mysql_query("SELECT * FROM $tableName");  
$arr_json = array();
while ($row = mysql_fetch_assoc($result)) {
   $json = json_encode($row);
   $arr_json[] = $json;
}

看起来是j08691的答案,看来我可能误会了.

Looking a j08691's answer, it looks like I might have misunderstood.

无论如何,如果您不知道自己有多少列,请执行以下操作:

Anyway, if you don't know how many columns you have, do this:

$arr = array();
while ($row = mysql_fetch_assoc($result)) {
   $arr2 = array();
   foreach ($row as $val) $arr2[] = $val;
   $arr[] = $arr2;
}

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