Python3.3 type =文件名错误 [英] Python3.3 type=file NameError

问题描述

import sys
import argparse
parser = argparse.ArgumentParser(description='blah blah')
parser.add_argument('reference_file', type=file, help='blah blah')
args = parser.parse_args()

运行上述脚本时，出现以下错误.

When I run the above script I get the following error.

NameError: name 'file' is not defined

我不知道怎么了. Python 3.3不允许这样做吗?请帮忙.

I don't know what's wrong. Is this not allowed in Python 3.3? Please help.

推荐答案

file是open的别名，已在Python 3中删除.

file was an alias for open, which has been removed in Python 3.

您可以改用open，但是argparse有一个更好的选择:[FileType()工厂类型]:

You can use open instead, but argparse has a better option: the [FileType() factory type]:

parser.add_argument('reference_file', type=argparse.FileType('r'), help='blah blah')

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