未定义对"sqrt"的引用 [英] undefined reference to `sqrt'
问题描述
我程序的一部分是计算浮点数sqrt.
编写sqrt(1.0f);时成功编译程序，但是编写sqrt(-1.0f);时成功
编译失败并显示undefined reference to 'sqrt'-我想在这种情况下，将返回nan值...
我用gcc编译程序.
当我用Visual Studio编译它时，它对sqrt的否定参数编译成功.
如何解决问题
谢谢
Part of my program is to calculate sqrt of float number.
When I write sqrt(1.0f); I success to compile the program,but when I write sqrt(-1.0f);
the compilation fails with undefined reference to 'sqrt' - I suppose that in this case the nan value will be returned...
I compile the program uing gcc.
When I compile it with visual studio it is compiled successfuly with negative argument to sqrt.
How the problem could be solved
Thank you
推荐答案
您必须在大多数基于Unix的系统上添加-lm标志，例如:
You have to add the -lm flag on most Unix-based systems, as in:
编译使用:
gcc -c file.c
，然后使用以下链接:
gcc -o program file.o -lm
或者，如果您不想将两个编译步骤分开，只需编写:
Or if you don't want to separate the two compilation steps, simply write:
gcc -o program file.c -lm
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