SQL“用于XML路径" -嵌套结果 [英] SQL "For XML Path" - nested results

问题描述

我有这个表结构. YearPart，MonthPart和DatePart包含了它们所描述的内容……例如:2011、1、19(分别)

I have this table structure. YearPart, MonthPart and DatePart contain what they describe... EX: 2011, 1, 19 (respectively)

DECLARE @agenda AS TABLE    (
  PID INT IDENTITY(1,1) PRIMARY KEY,
  YearPart int,
  MonthPart int,
  DayPart int,
  lib_title nvarchar(200),
  [filename] nvarchar(255),
  meta_value nvarchar(2000)
)

使用此示例数据:

INSERT INTO @agenda VALUES (2010, 12, 4, 'Test Record', '', '')
INSERT INTO @agenda VALUES (2011, 1, 3, 'Another Record', '', '')
INSERT INTO @agenda VALUES (2011, 1, 3, 'Fred Birthday', '', '')
INSERT INTO @agenda VALUES (2011, 1, 4, 'Work Day', '', '')
INSERT INTO @agenda VALUES (2011, 12, 6, '2nd Test Record', '', '')

我想要的是这样的XML输出:

What I want, is an XML output like this:

<root>
  <Year Year="2010">
    <Month Month="12">
      <Day Day="4">
        <Item RecordName="Test Record" RecordID="1" />
      </Day>
    </Month>
  </Year>
  <Year Year="2011">
    <Month Month="1">
      <Day Day="3">
        <Item RecordName="Another Record" RecordID="2" />
        <Item RecordName="Geoffrey Birthday" RecordID="3" />
      </Day> 
      <Day Day="4">
        <Item RecordName="Work Day" RecordID="4" />
      </Day>
    </Month>
    <Month Month="12">
      <Day Day="6">
        <Item RecordName="2nd Test Record" RecordID="5" />
      </Day>
    </Month>
  </Year>
</root>

到目前为止，我还无法使嵌套正常工作.我通常以分组结束(例如，当只有一个Year = 2011元素时，我会得到多个).

So far, I haven't been able to get the nesting to work right. I usually end up with the grouping off (for example, I get multiple Year=2011 elements, when there should only be one).

如果无法做到这一点，我总是可以在.NET网站上创建XML ...

If this can't be done, I can always create the XML on the .NET site...

推荐答案

可以做到.

select 
  a1.YearPart as '@Year',
  ( select MonthPart as '@Month',
      (select DayPart as '@Day',
         (select
            lib_title as '@RecordName', 
            PID as '@RecordID'
          from @agenda as a4
          where a4.DayPart = a3.DayPart and
                a4.MonthPart = a2.MonthPart and
                a4.YearPart = a1.YearPart
          for xml path('Item'), type         
         )
       from @agenda as a3
       where a3.YearPart = a1.YearPart and
             a3.MonthPart = a2.MonthPart
       group by a3.DayPart
       for xml path('Day'), type      
      )
    from @agenda as a2
    where a1.YearPart = a2.YearPart
    group by a2.MonthPart
    for xml path('Month'), type
  )  
from @agenda as a1
group by YearPart
for xml path('Year'), root

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