嵌套范围和Lambda [英] Nested Scopes and Lambdas

问题描述

def funct():
    x = 4
    action = (lambda n: x ** n)
    return action

x = funct()
print(x(2)) # prints 16

...我不太明白为什么2被自动分配给n?

... I don't quite understand why 2 is assigned to n automatically?

推荐答案

n是funct返回的匿名函数的参数.完全等同的funct定义是

n is the argument of the anonymous function returned by funct. An exactly equivalent defintion of funct is

def funct():
    x = 4
    def action(n):
        return x ** n
    return action

这种形式还有其他意义吗?

Does this form make any more sense?

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