修改嵌套列表元素的最优雅方法 [英] Most elegant way to modify elements of nested lists in place

问题描述

我有一个二维列表，如下所示:

I have a 2D list that looks like this:

table = [['donkey', '2', '1', '0'], ['goat', '5', '3', '2']]

我想将最后三个元素更改为整数，但是下面的代码却很难看:

I want to change the last three elements to integers, but the code below feels very ugly:

for row in table:
    for i in range(len(row)-1):
        row[i+1] = int(row[i+1])

但是我宁愿有这样的东西:

But I'd rather have something that looks like:

for row in table:
    for col in row[1:]:
        col = int(col)

我认为应该有一种方法可以编写上面的代码，但是分片创建的迭代器/新列表与原始列表是分开的，因此引用不会继续存在.

I think there should be a way to write the code above, but the slice creates an iterator/new list that's separate from the original, so the references don't carry over.

有没有办法获得更多的Python解决方案?

Is there some way to get a more Pythonic solution?

推荐答案

for row in table:
    row[1:] = [int(c) for c in row[1:]]

上面看起来更像Python吗?

Does above look more pythonic?

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