NetLogo的两个代理集操作 [英] NetLogo two agentsets operations

问题描述

我有两个代理集.是否有查找功能:

I have two agentsets. Are there functions for finding:

1. 两个(交叉点)中都存在的代理的代理集
2. 在一个而不是另一个中存在的代理的代理集

我发现手动执行此操作非常困难，尤其是在三元组ask

I'm finding it very difficult to implement this by hand, especially when it's needed inside of a triple ask

理想用法类似于with语法:

let cross set1 and-in set2
let uniq set1 with [color = red] not-in set2

简单的事情，例如"A代理是否在X代理集中?"有问题

Simple things like "Is agent A in the agentset X?" are problematic

推荐答案

对于第一个，您使用turtle-set原语.对于第二个，您需要member?原语，它也适用于代理集.因此:

For the first one you use the turtle-set primitive. For the second one you need the member? primitive, which also works on agentsets. As such:

to setup
  ca
  create-turtles 10 [set color red]
  create-turtles 10 [set color blue]
  let red-ones turtles with [color = red]
  let blue-ones turtles with [color = blue]

  ;join 2 agent sets
  let joinset (turtle-set red-ones blue-ones)
  show joinset

  let even-ones (turtles with [who mod 2 = 0])
  ;subtract even-ones from red-ones
  let subtractset red-ones with [not member? self even-ones]
  show subtractset
end

这篇关于NetLogo的两个代理集操作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！