覆盖删除运算符 [英] Override delete operator

问题描述

我想在我的课程中重写delete运算符.这是我想做的，但没有成功.

I want to override delete operator in my class. Here's what I am trying to do,but not succeeding.

class Complex{              
    void *operator new(size_t s);
    void operator delete(void *ptr);
};

void Complex::operator delete(void *ptr){
    delete ptr;
}

我得到了错误:

删除void *未定义

deleting void* is undefined

推荐答案

如错误消息所示，您不能delete和void*.试试这个:

As the error message indicates, you can't delete a void*. Try this:

// See http://www.informit.com/guides/content.aspx?g=cplusplus&seqNum=40

#include <new> // for size_t

class Complex
{
public:
 Complex() {}
 ~Complex() {}
 static void* operator new (size_t size) {
  return new char[size];
 }
 static void operator delete (void *p) {
  return delete[] static_cast<char*>(p);
 }
};

int main () {
  Complex *p = new Complex;
  delete p;
}

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