nginx位置正则表达式-字符类别和匹配范围 [英] nginx location regex - character class and range of matches

问题描述

我正在尝试为路径/s/<4-6 character string here>设置正则表达式，在其中将4-6字符串捕获为$ 1.

I am trying to setup a regex for the path /s/<4-6 character string here> where I capture the 4-6 character string as $1.

我尝试使用以下两个条目，但都失败了

I tried using the following two entries, but both fail

location ~ ^/s/([0-9a-zA-Z]){4,6}+$ { ...

location ~ ^/s/([0-9a-zA-Z]{4,6})+$ { ...

第一个出现未知指令"，第二个出现"pcre_compile()失败:缺少)"

The first one comes up with 'unknown directive' and the second comes up with 'pcre_compile() failed: missing )'

编辑

此位置将提供以下路线:

The following routes would be served by this location:

/s/1234 (and I would capture '1234' in $1)
/s/12345 (and I would capture '12345' in $1)
/s/123456 (and I would capture '123456' in $1)
/s/abcd (and I would capture 'abcd' in $1)
/s/abcde (and I would capture 'abcde' in $1)
/s/abcdef (and I would capture 'abcdef' in $1)
/s/a1b2c (and I would capture 'a1b2c' in $1)

此位置不提供以下路线:

The following routes would NOT be served by this location:

/s/1
/s/12
/s/123
/s/a
/s/ab
/s/abc
/s/abc1234
/s/12345678

等...

推荐答案

如果要捕获4到6个字符，为什么不将量词放在捕获括号内?

If you want to capture 4 to 6 characters, why you don't have put the quantifier inside the capture parenthesis?

类似的东西:

location ~ "^/s/([0-9a-zA-Z]{4,6})$" {...

在正则表达式和块控制中都使用大括号，您必须在正则表达式中使用双引号(单引号或双引号)(<-Wiki Nginx)

Curly braces are used both in regex and for block control, you must enclose your regex with quotes (single or double) (<-- wiki nginx)

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