打字稿:如何从2套不同的对象集中获取具有相同属性值但键不同的对象 [英] typescript: How to get objects with the same property values but different keys from 2 different sets of Objects
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问题描述
我必须从状态数据表格中获取Json的集合
I have to sets of Json got from the form the state data
objetSet1:
{id: 12, name: 'Foo Bar', email: 'foo@bar.com'},
{id: 23, name: 'Bar Foo', email: 'bar@foo.com'},
{id: 61, name: 'Barbell', email: 'barbell@mail.com'},
{id: 45, name: 'Joe Ocean', email: 'joe@ocean.com'}
objectSet2:
{ObjectId:15, name: 'someone', email: 'someone@mail.com'},
{ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
{ObjectId: 72, name: 'seven ', email: 'seven@mail.com'},
{ObjectId: 23, name: 'five ', email: 'five@mail.com'}
我实际上是在寻找一种使该表达式具有动态性的方法
I was actually looking for a way to get this expression to be dynamic
objectSet2 = objectSet2.filter(object => object.ObjectId === '23')
objectSet1中的值代替了23个静态值
instead of 23 static value, the value from objectSet1 corresponding
结果应包含第一个对象集上存在ID的项目
预期输出:
objectSet2:
{ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
{ObjectId: 23, name: 'five ', email: 'five@mail.com'}
推荐答案
Yoy接近了，只需要添加一个新的过滤器，像这样:
Yoy were close, just needed to add a new filter like this:
objetSet1 = [{id: 12, name: 'Foo Bar', email: 'foo@bar.com'},
{id: 23, name: 'Bar Foo', email: 'bar@foo.com'},
{id: 61, name: 'Barbell', email: 'barbell@mail.com'},
{id: 45, name: 'Joe Ocean', email: 'joe@ocean.com'}];
objectSet2 = [{ObjectId:15, name: 'someone', email: 'someone@mail.com'},
{ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
{ObjectId: 72, name: 'seven ', email: 'seven@mail.com'},
{ObjectId: 23, name: 'five ', email: 'five@mail.com'}];
var result = objectSet2.filter((obj2)=>objetSet1.filter((obj1)=>obj1.id==obj2.ObjectId).length>0)
console.log(result);
请注意obj1.id==obj2.ObjectId的比较.当内部过滤器上的正匹配计数大于零时，它返回true.这就是外部过滤器的答案.
Please note obj1.id==obj2.ObjectId comparison. It's returning true when the count of positive matches on the inner filter is greater than zero. Then this is the answer for the outer filter.
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