如何使用Node.js获取当前脚本的路径? [英] How do I get the path to the current script with Node.js?

问题描述

我如何在Node.js中获取脚本的路径?

How would I get the path to the script in Node.js?

我知道有process.cwd，但这仅是指脚本被调用的目录，而不是脚本本身的目录.例如，假设我在/home/kyle/中，然后运行以下命令:

I know there's process.cwd, but that only refers to the directory where the script was called, not of the script itself. For instance, say I'm in /home/kyle/ and I run the following command:

node /home/kyle/some/dir/file.js

如果我呼叫process.cwd()，则会得到/home/kyle/，而不是/home/kyle/some/dir/.有没有办法获取该目录?

If I call process.cwd(), I get /home/kyle/, not /home/kyle/some/dir/. Is there a way to get that directory?

推荐答案

我在仔细阅读了文档后发现了它.我正在寻找的是 __filename 和 __dirname 模块级变量.

I found it after looking through the documentation again. What I was looking for were the __filename and __dirname module-level variables.

• __filename是当前模块的文件名.这是当前模块文件的解析绝对路径. (例如:/home/kyle/some/dir/file.js)
• __dirname是当前模块的目录名称. (例如:/home/kyle/some/dir)

• __filename is the file name of the current module. This is the resolved absolute path of the current module file. (ex:/home/kyle/some/dir/file.js)
• __dirname is the directory name of the current module. (ex:/home/kyle/some/dir)

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