获取当前脚本的基本目录 [英] Get base directory of current script

问题描述

这是我的脚本的网址:localhost/do/index.php

This is the url of my script: localhost/do/index.php

我想要一个返回localhost/do的变量或函数(类似于$_SERVER['SERVER_NAME'].'/do')

I want a variable or a function that returns localhost/do (something like $_SERVER['SERVER_NAME'].'/do')

推荐答案

尝试:

$url = $_SERVER['REQUEST_URI']; //returns the current URL
$parts = explode('/',$url);
print_r($parts);

$url = $_SERVER['REQUEST_URI']; //returns the current URL
$parts = explode('/',$url);
$dir = $_SERVER['SERVER_NAME'];
for ($i = 0; $i < count($parts) - 1; $i++) {
 $dir .= $parts[$i] . "/";
}
echo $dir;

这应该返回localhost/do/

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