使用python的long类型的numpy数组 [英] numpy array using python's long type

问题描述

我正在尝试创建类型为long的numpy数组(即Python的long，而不是numpy的long = int64).

I am trying to create a numpy array with type long (that is, Python's long, not numpy's long = int64).

如果我这样做:

m = np.eye(6, dtype=long)
print(m.dtype)

这将输出int64;也就是说，它们不是Python long.

This outputs int64; i.e., they are not Python longs.

有没有办法创建一个每个元素的类型都为long的numpy数组?还是这是numpy不支持的某些固定宽度与非固定宽度问题?如果是这样，是否有任何库(最好具有类似numpy的C语言API)可以做到这一点?

Is there any way to create a numpy array with each element being of type long? Or is this some fixed-width versus non-fixed-width problem that numpy doesn't support? If so, is there any library (preferably with a nice C API like numpy's) that can do this?

推荐答案

Python的长整数类型不是本机numpy类型，因此您必须 使用object数据类型. object类型的numpy数组的元素可以是任何python对象.

Python's long integer type is not a native numpy type, so you will have to use the object data type. The elements of an numpy array with object type can be any python objects.

例如，

In [1]: x = np.array([1L, 2L, 3L], dtype=object)

In [2]: x
Out[2]: array([1L, 2L, 3L], dtype=object)

In [3]: x[0]
Out[3]: 1L

In [4]: type(x[0])
Out[4]: long

这对您是否有用取决于您要对多头数组进行的操作.

Whether or not this is useful for you depends on what you want to do with the array of longs.

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