带有浮点数的Numpy bincount() [英] Numpy bincount() with floats
本文介绍了带有浮点数的Numpy bincount()的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试获取浮点类型的numpy数组的bincount:
I am trying to get a bincount of a numpy array which is of the float type:
w = np.array([0.1, 0.2, 0.1, 0.3, 0.5])
print np.bincount(w)
如何将bincount()与浮点值而不是int一起使用?
How can you use bincount() with float values and not int?
推荐答案
您想要这样的东西吗?
>>> from collections import Counter
>>> w = np.array([0.1, 0.2, 0.1, 0.3, 0.5])
>>> c = Counter(w)
Counter({0.10000000000000001: 2, 0.5: 1, 0.29999999999999999: 1, 0.20000000000000001: 1})
或者更好的输出:
Counter({0.1: 2, 0.5: 1, 0.3: 1, 0.2: 1})
然后您可以对其进行排序并获取您的值:
You can then sort it and get your values:
>>> np.array([v for k,v in sorted(c.iteritems())])
array([2, 1, 1, 1])
bincount
的输出对于浮点数没有意义:
The output of bincount
wouldn't make sense with floats:
>>> np.bincount([10,11])
array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1])
因为没有定义的浮点数序列.
as there is no defined sequence of floats.
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