numpy-在特定位置重叠2个矩阵 [英] Numpy - Overlap 2 matrices at a particular position

问题描述

美好的一天，

让我们说我有一个200 * 200的矩阵A和一个50 * 50的矩阵B.我想将B放置在点A上，例如(175,175).问题是B超出了A的范围，但我真正需要的是将超出的范围剪掉.

Lets say I have a 200*200 matrix A, and 50*50 matrix B. I want B to be placed on the point A at say (175,175). The problem with this is that B exceeds the bounds of A, but what I really need is for the exceeded bounds to clip off.

我尝试做这样的事情:A [y:yRange + y，x:xRange + x] = B，但这会引发超出范围的错误.有什么简单的方法可以将这2个代码重叠在一个位置上，而不必求助于慢的for循环.

I tried doing something like this: A[y:yRange+y, x:xRange+x] = B, but this will throw the out of bounds error. Is there any easy way to overlap these 2 at a position without resorting to a slow for loop.

推荐答案

您可以将B的一个片段复制到A的一个片段上，例如:

You can copy a slice of B onto a slice of A, for example:

 A[175:, 175:] = B[:25, :25]

这是对numpy索引的直接使用.

It's a straight forward use of numpy indexing.

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