以编程方式禁用UIButton [英] Disable UIButton programmatically

问题描述

我很困惑为什么此代码无法正常工作.我有一个要在用户未登录时禁用的登录按钮.

I'm stumped at why this code isn't working. I have a login button that I want to disable when the user isn't logged in.

我的.h文件中有一个UIButton，就像这样:

I have a UIButton delared in my .h file like so:

   IBOutlet UIButton *myBtn;

我已经在Interface Builder中为该按钮设置了一个引用插座.

I've set up a referencing outlet in Interface Builder to this button.

在我的.m文件中，我尝试过:

In my .m file, I've tried:

[myBtn setEnabled: NO];

和

myBtn.enabled = NO;

但是这些都不禁用我正在使用的条件语句中的按钮.(我想在用户成功登录后禁用登录按钮)

But neither of these disable the button in the conditional statement I'm in. (I want to disable the login button when the user successfully logs in)

我可以使用同一屏幕上的其他两个按钮来执行此操作，因此我知道代码是正确的.我不会抛出任何错误，因此我认为该对象存在.对myBtn的引用也会在XCode中更改颜色，因此它似乎是有效的引用.

I'm able to do this with two other buttons on the same screen, so I know the code is correct. I don't throw any errors, so I think the object exists. The references to myBtn change color in XCode, too, so it appears to be a valid reference.

我一定很想念东西.我在这里做错了什么? (我是Windows开发人员，在Objective-C相对较新)

I must be missing something. What am I doing wrong here? (I'm a Windows developer, relatively new at Objective-C)

推荐答案

在我看来还可以.您是合成按钮吗?试试

It seems ok to me. Are you synthesizing the button? Try

self.myBtn.enabled = NO;

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