以编程方式禁用单击UIButton时的突出显示 [英] Programmatically Disable Highlight on Click of UIButton

问题描述

必须有办法做到这一点，但我找不到它。我有一个按编程方式创建的按钮：

There must be a way to do this, but I can't find it. I have a button I have created programmatically:

UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
button.frame = CGRectMake(25, self.view.frame.size.height/4, 200, 350);
[button setTitle:@"Inbox" forState:UIControlStateNormal];
[button addTarget:self action:@selector(popViewController:) forControlEvents:UIControlEventTouchUpInside];
[self.view addSubview:button];

我想要的只是按钮在触摸时不以任何方式突出显示或改变外观。到目前为止，我在创建按钮时尝试了以下操作：

All I want is for the button not to highlight or change in appearance in any way when it is touched. So far I have tried the following when creating the button:

[button setBackgroundImage:[UIImage imageNamed:nil] forState:UIControlStateSelected | UIControlStateHighlighted];

AND

[button setBackgroundImage:nil forState:UIControlStateSelected];

AND

[button setAdjustsImageWhenHighlighted:NO];

AND

button.showsTouchWhenHighlighted = NO;

然后在我尝试的按钮操作中：

Then in the button action I tried:

[sender setHighlighted:!sender.isHighlighted];

AND

[sender setSelected:!sender.isSelected];

这些都不起作用。

推荐答案

使您的UIButton成为自定义按钮，然后对其应用UIImage背景。按下时不会突出显示或更改

Make your UIButton a custom button and then apply a UIImage background to it. It won't highlight or change when pressed

UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom];

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