如何比较从url到NSutf8stringencoding的字符串，返回带有正常字符串@"1"的1或0. [英] how to compare a string from url to NSutf8stringencoding return 1 or 0 with normal string @"1"

问题描述

我需要使用NSutf8stringencoding比较url中的字符串以返回1或0，但是即使字符串的值为1，它也总是返回0.

I need to compare a string from an url using NSutf8stringencoding in order to return 1 or 0, but it always returns 0 even if the string has value 1.

NSString *strURL = [NSString stringWithFormat:@"http://localhost/signup/login.php?username=%@&password=%@",username.text,password.text];

// to execute php code
NSData *dataURL = [NSData dataWithContentsOfURL:[NSURL URLWithString:strURL]];

// to receive the returend value
NSString *strResult = [[NSString alloc] initWithData:dataURL 
encoding:NSUTF8StringEncoding];

// print the data in strResult
NSLog(@"%@",strResult);

if ([strResult isEqualToString:@"1"])
{
    // I need to get the control for main navigation controller 
    login2ViewController *controller = [[login2ViewController alloc] initWithNibName:@"login2ViewController" bundle:nil];
    controller.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal;
    [self presentModalViewController:controller animated:YES ];

}else
{
    // invalid information
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"alert" message:@"Invalid Information" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
    [alert show];
    return;  
}

但是，即使strResult中的内容是1，它也始终显示无效信息. 我用NSlog打印了该值. NSLog的输出:

But it always show invalid informartion even if the content in strResult is 1. I printed that value by NSlog. The output from NSLog:

2012-12-11 16:06:08.156 friend finder[277:11603] 
1

如何将字符串与@"1"进行比较?

How can I compare that string with @"1"?

推荐答案

尝试以下操作-strResult中可能会有其他空格字符(例如回车):

Try the following - there could be additional whitespace characters in the strResult (like carriage returns):

if ([strResult rangeOfString:@"1"].length > 0) {
    // Do something...
}

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