sqlite3_step(statement)== SQLITE_DONE始终为false [英] sqlite3_step(statement) == SQLITE_DONE is always false

问题描述

我正在尝试在我的应用程序中注册用户.
我有一个带有3 textfields (username, password and confirmpassword)和一个submit按钮的视图控制器.

I am trying to Sign up a user in my application.
I have a view controller with 3 textfields (username, password and confirmpassword) and a submit button.

按下提交按钮时，将调用以下方法:

The following method is called when submit button is pressed:

-(IBAction)addUser
{
    NSString *tempUser,*tempPass, *tempConfPass;
    tempUser = [[NSString alloc]init];
    tempPass = [[NSString alloc]init];
    tempConfPass = [[NSString alloc]init];
    tempUser = [NSString stringWithFormat:@"%@",_mUserName.text];
    tempPass = [NSString stringWithFormat:@"%@",_mPassword.text];
    tempConfPass = [NSString stringWithFormat:@"%@",_mConfPassword.text];
    signupUser = [[UseDb alloc]init];

    flagUser = [signupUser addNewUser:_mUserName.text:_mPassword.text:_mConfPassword.text];
    if(flagUser)
    {
        myAlertViewUser = [[UIAlertView alloc] initWithTitle:@"Error" message:@"User Added"
                                                    delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil];

        [myAlertViewUser show];
    }
    else {
       _mStatus.text = @"failed to add user";
       myAlertViewUser = [[UIAlertView alloc] initWithTitle:@"Error" message:@"passwords don't match"
                                delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil];

       [myAlertViewUser show];
    }
}

，此方法由addUser方法调用:

-(BOOL)addNewUser:(NSString *)newUser :(NSString *)newPassword :(NSString *)confirmPass
{
   NSLog(@"%@....%@...%@",newUser, newPassword, confirmPass);
    sqlite3_stmt    *statement;
    const char *dbpath = [_mDatabasePathDb UTF8String];

    if (sqlite3_open(dbpath, &_mDb) == SQLITE_OK && [newPassword isEqualToString:confirmPass] && ![newUser isEqualToString:@""] && ![newPassword isEqualToString:@""])
    {
        self.userName = [NSString stringWithFormat:@"%@",newUser];
        self.password = [NSString stringWithFormat:@"%@",newPassword];

        NSString *insertSQL = [NSString stringWithFormat:
                               @"INSERT INTO USERDETAIL VALUES (\"%@\",\"%@\",\"%@\", \"%@\",\"%@\", \"%@\",\"%@\", \"%@\",\"%@\", \"%@\",\"%@\")",self.userName,self.password,@"",@"",@"",@"",@"",@"",@"",@"",@"" ];

        NSLog(@"%@",insertSQL);
        const char *insert_stmt = [insertSQL UTF8String];
        sqlite3_prepare_v2(_mDb, insert_stmt, -1, &statement, NULL);

        if (sqlite3_step(statement) == SQLITE_DONE)
        {
            return YES;
            /*    mUserName.text = @"";
             mPassword.text = @"";
             mConfPassword.text = @""; */

        }
        else {

            NSLog(@"failed to add user");
        }

        sqlite3_finalize(statement);
        sqlite3_close(_mDb);
    }
}

在addNewUser方法中，if (sqlite3_step(statement) == SQLITE_DONE)总是显示为false，语句在

In the addNewUser method, if (sqlite3_step(statement) == SQLITE_DONE) is always coming out to be false, statement has some value before

sqlite3_prepare_v2(_mDb, insert_stmt, -1, &statement, NULL); 

，但是在执行上述语句后变为nil.我不明白为什么会这样.
请帮助.

but turns to nil after the above statement is executed. I don't understand why that is happening.
Please help.

推荐答案

这可能与您正在执行的检查有关，请尝试使用SQLITE_OK.它在 docs 中表示为在旧版界面(旧界面)中，返回值将为 SQLITE_BUSY，SQLITE_DONE，SQLITE_ROW，SQLITE_ERROR或SQLITE_MISUSE .使用"v2"界面，也可能会返回任何其他结果代码或扩展结果代码.

This can be an issue with the check you are doing, try SQLITE_OK. Its said here in docs as In the legacy interface(older interface), the return value will be either SQLITE_BUSY, SQLITE_DONE, SQLITE_ROW, SQLITE_ERROR, or SQLITE_MISUSE. With the "v2" interface, any of the other result codes or extended result codes might be returned as well.

if (sqlite3_prepare_v2(_mDb, insert_stmt, -1, &statement, nil) == SQLITE_OK)
        {
            if (sqlite3_step(statement) == SQLITE_DONE)
            {
               return YES;
            }
            else 
            {
              NSLog(@"failed to add user");
            }
            sqlite3_finalize(statement);
        }

您还可以找到类似的问题及其答案这里

you can also find a similar question and its answer here

在prepare语句后插入花括号，并在finalize语句后将其关闭.当您获得SQLITE_MISUSE时，可能是该例程被不适当地调用.可能是在已经完成的预准备语句或先前返回SQLITE_ERROR或SQLITE_DONE的语句上调用了它.或者可能是两个或多个线程同时使用同一数据库连接.

Insert a curly brace after the prepare statement and close it after finalize statement. As you get SQLITE_MISUSE, it can be that this routine was called inappropriately. Perhaps it was called on a prepared statement that has already been finalized or on one that had previously returned SQLITE_ERROR or SQLITE_DONE. Or it could be the case that the same database connection is being used by two or more threads at the same moment in time.

希望这会有所帮助:)

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