在Ocaml中缩写构造函数名称 [英] Abbreviating constructor names in Ocaml
问题描述
我有两个模块.一个定义了一个变体类型:
I have two modules. One defines a variant type:
module A = struct
type foo = Bar of material | Baz | Boo
(* other stuff *)
end
,我希望能够将foo
的变体既用作构造函数,又用作另一个模块的左侧
and I would like to be able to use foo
's variants both as constructors and as left-hand-sides in another module
module B = struct
type foo = A.foo (* I can abbreviate A.foo by assigning it a local alias *)
let f (x : foo) = match x with
| Bar m -> Bar (g m) (* Any way to abbreviate Bar and friends? *)
| Baz | Boo -> x
end
但根据引用命名对象" 我必须在变体名称前加上 module-path :
but per "referring to named objects" I have to prefix the variant names with a module-path:
let f (x : foo) = match x with
| A.Bar m -> A.Bar (g m)
| A.Baz | A.Boo -> x
有什么方法可以跳过,避免使用缺少open
的模块路径,并从A
中提取所有其他内容?
Is there any way to skip avoid using the module path short of open
ing and pulling in all the other stuff from A
?
推荐答案
您可以在本地打开A:
let f (x : foo) = A.(match x with
| Bar m -> Bar (g m)
| Baz | Boo -> x)
或
let f (x : foo) =
let open A in
match x with
| Bar m -> Bar (g m)
| Baz | Boo -> x)
您可以在子模块中定义Bar
,以便暴露更少的内容:
You can define Bar
in a submodule so that less things are exposed:
module A = struct
module BasicDataAndOps = struct
type foo = Bar of material | Baz | Boo
end
open BasicDataAndOps
(* other stuff *)
end
module B = struct
open A.BasicDataAndOps
...
要在模式之外使用,可以在B中定义一个智能构造函数":
For use outside of patterns, you can define a "smart constructor" in B:
let bar m = A.Bar m
ETA:我忘记了重新声明类型定义的可能性,这在Ashish Argwal的答案type foo = A.foo = Bar of material | Baz | Boo
中有所描述.鉴于您的示例中已经输入了缩写,这是最好的答案.
ETA: I forgot about the possibility to restate type definition, described in Ashish Argwal's answer: type foo = A.foo = Bar of material | Baz | Boo
. Given that you already have type abbreviation in your example, this is the best answer.
关于基于类型的标签消除歧义这可能会有所帮助,但可能不会被该语言接受.
There is some work on type-based label disambiguation which could be helpful, but it may not get accepted into the language.
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