倍频程基础知识:如何从向量分配变量 [英] Octave basics: How to assign variables from a vector

问题描述

也许我被Python宠坏了，但是Octave是否允许直接从向量分配变量的值?也就是说，做类似的事情

Maybe I'm spoiled by Python, but does Octave allows one to assign the values of variables directly from a vector? That is, doing something like

a,b,c=[5,6,7]

将得到a=5, b=6, c=7. 我已经尝试过多种组合来编写上面的表达式，但是还没有运气...

will result with a=5, b=6, c=7. I have tried many combinations of writing the expression above, but no luck yet ...

推荐答案

这可以通过使用"{...}"构造一个单元格数组，然后通过"{:}"将其转换为逗号分隔的列表来完成:

This can be done by constructing a cell array with "{...}" and converting this to a comma separated list via "{:}":

[a b c] = {5 6 7}{:}
a =  5
b =  6
c =  7

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