车辆收到RSU范围以外的信标消息 [英] Vehicles Receive Beacon Messages outside RSU Range

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问题描述

我正在OMNET ++中研究Veins框架.我在.ned文件中设置RSU的属性,如下所示:

I am working on Veins framework, inside OMNET++. I set the property of RSU inside .ned file as follow:

 @display("p=150,140;b=10,10,oval;r=90");

tkenv在RSU周围显示一个圆圈,但是车辆接收到的信标不在范围内(圆圈).

The tkenv shows a circle around RSU, but the vehicles received beacons outside the range (circle).

如何调整RSU到Circle的传输范围?

How can I adjust the transmission range of RSU to the Circle?

推荐答案

添加显示字符串标签r只是在图形输出中添加了一个圆圈.它不会影响仿真.

Adding a display string tag of r is just adding a circle to the graphical output; it does not influence the simulation.

如果将传输范围"定义为接收概率为零的点,则可以基于天线的传输功率和无线电的灵敏度(均在omnetpp.ini中设置)来计算该点,以及使用的路径损耗和衰落模型(在config.xml中设置).如果更改这些参数和模型,则将更改此传输范围".

If you define the "transmission range" as the point where the probability of reception is zero, you can calculate this point based on the transmission power at the antenna and the sensitivity of the radio (both set in omnetpp.ini), as well as the used path loss and fading models (set in config.xml). If you change these parameters and models, you are changing this "transmission range".

但是,请注意,此范围与帧接收概率的相关性很小. Veins使用 MiXiM套件和方法将传输模型建模为二维(时间和时间).频率)的信号功率函数,这些函数会因路径损耗和衰落效应(随机的和确定性的,例如由于建筑物的影响)而改变. 如果帧的接收功率高于灵敏度阈值,则根据这些函数的信号,干扰和噪声除以计算出SINR并从中得出误码率,从而计算出其接收概率. 即使处于中等干扰水平,这也意味着即使大多数帧都远远高于灵敏度阈值,也无法对其进行解码(仅仅是因为它们的SINR太低).

Note, however, that this range has only little relevance to frame reception probability. Veins employs the MiXiM suite and approach to model transmissions as two-dimensional (time and frequency) functions of signal power that are modified by path loss and fading effects (both stochastic and deterministic, e.g., due to buildings). If a frame's receive power is above the sensitivity threshold, its reception probability is computed based on dividing these functions for signal, interference, and noise to derive the SINR and, from that, the bit error rate. Even at moderate interference levels, this means that most frames cannot be decoded even though they are well above the sensitivity threshold (simply because their SINR was too low).

只需重复一遍:我警告不要出于纯粹出于信息目的的目的而计算传输范围".理论上,您可以发送多远与您在中等繁忙的频道上可以发送多远没有任何关系.此效果 是用静脉建模的!

Just to repeat: I am warning against calculating a "transmission range" for anything other than purely informational purposes. How far you can send in theory has absolutely no relation to how far you can send on a moderately busy channel. This effect is modeled in Veins!

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