如何将变量从类函数回显到另一个文件 [英] How to echo variable from the class function to the other file

问题描述

我只是OOP PHP的初学者.我想发生的是将变量从函数内的类回显到其他文件.请看一下这段代码:

在class.library.php文件中:

class db_connect {

    // Other functions and variables here

    function settings() {
        $sql="SELECT * FROM lms_admin_settings";
        $result = $this->conn->query($sql);
        while($data = $result->fetch_assoc()) {
            $name = $data["name"];
        }
    }
}

和index.php文件中:

include("class.library.php");
$data = new db_connect;
$data->settings();

我要发生的事情是简单地将名为$name的变量从名为db_connect的类的settings()函数返回到index.php文件.

我尝试过这样的事情:

include("class.library.php");
$data = new db_connect;
$data->settings();
echo $name; // I tried this but didn't work, I put this just to make things more clearly.

请告诉我这样做的正确方法.

PS:请原谅我用来解释我的问题的术语.我只是一个初学者.随时欢迎您纠正我.

解决方案

您需要将$name设置为类中的公共变量. 像这样:

class db_connect {
    // We declare a public var
    public $name = "";

    function settings() {
        $sql="SELECT * FROM lms_admin_settings";
        $result = $this->conn->query($sql);
        while($data = $result->fetch_assoc()) {
            $this->name = $data["name"];
        }
    }
}

然后，您应该能够在index.php中像这样访问您的var:

$data = new db_connect;
$data->settings();
echo $data->name;

您可以阅读以了解有关var和函数可见性的更多信息 Php文档

I am just a beginner at OOP PHP. What I want to happen is to echo the variable from the class inside the function to other file. Please take a look at this code:

in class.library.php file:

class db_connect {

    // Other functions and variables here

    function settings() {
        $sql="SELECT * FROM lms_admin_settings";
        $result = $this->conn->query($sql);
        while($data = $result->fetch_assoc()) {
            $name = $data["name"];
        }
    }
}

and in index.php file:

include("class.library.php");
$data = new db_connect;
$data->settings();

what I want to happen is to simply echo the variable named $name from settings() function of class named db_connect to index.php file.

I tried something like this:

include("class.library.php");
$data = new db_connect;
$data->settings();
echo $name; // I tried this but didn't work, I put this just to make things more clearly.

Please tell me the correct way of doing that.

PS: Pardon for what terms that I've used to explain my problem. I am just a beginner. You are always welcome to correct me.

解决方案

You need to set $name as a public var into your class. Like this:

class db_connect {
    // We declare a public var
    public $name = "";

    function settings() {
        $sql="SELECT * FROM lms_admin_settings";
        $result = $this->conn->query($sql);
        while($data = $result->fetch_assoc()) {
            $this->name = $data["name"];
        }
    }
}

Then you should be able to access your var like this in index.php:

$data = new db_connect;
$data->settings();
echo $data->name;

You can read this to learn more about vars and function visibility Php doc

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