PHP类:从被调用方法访问调用实例 [英] PHP Classes: get access to the calling instance from the called method

问题描述

对不起这个奇怪的主题，但我不知道该如何用其他方式表达.

sorry for that weird subject but I don't know how to express it in an other way.

我正在尝试从调用类访问方法.像本例一样:

I'm trying to access a method from a calling class. Like in this example:

class normalClass {
     public function someMethod() { 
          [...]
          //this method shall access the doSomething method from superClass
     }
}

class superClass {
     public function __construct() {
          $inst = new normalClass;
          $inst->someMethod();
     }
     public function doSomething() {
          //this method shall be be accessed by domeMethod form normalClass
    }
}

两个类都不通过继承关联，我不想将函数设置为静态.

Both classes are not related by inheritance and I don't want to set the function to static.

有什么方法可以实现?

感谢您的帮助！

推荐答案

您可以像这样将引用传递给第一个对象:

You can pass a reference to the first object like this:

class normalClass {
    protected $superObject;
    public function __construct(superClass $obj) {
        $this->superObject = $obj;
    }

    public function someMethod() { 
        //this method shall access the doSomething method from superClass
        $this->superObject->doSomething();  
    }
}

class superClass {
    public function __construct() {
          //provide normalClass with a reference to ourself
          $inst = new normalClass($this);
          $inst->someMethod();
    }
    public function doSomething() {
          //this method shall be be accessed by domeMethod form normalClass
    }
}

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