在OpenCV中绘制矩形 [英] Draw rectangle in OpenCV

问题描述

我想使用此功能在OpenCV中绘制一个矩形:

I want to draw a rectangle in OpenCV by using this function:

rectangle(Mat& img, Rect rec, const Scalar& color, int thickness=1, int lineType=8, int shift=0 )

但是当我使用它时，我遇到了一些错误.我的问题是:任何人都可以用示例解释该功能吗?我找到了一些示例，但具有另一个功能:

But when I use it I am facing some errors. My question is: can anyone explain the function with an example? I found some examples but with another function:

rectangle(Mat& img, Point pt1, Point pt2, const Scalar& color, int thickness=1, int lineType=8, int shift=0)

关于第二个功能的此示例:

This example on the second function:

rectangle(image, pt2, pt1, Scalar(0, 255, 0), 2, 8, 0);

我了解此功能，但是使用第一个功能时，我遇到了参数Rect中的问题.我不知道该如何致命?

This function I understand, but with the first function I'm facing a problem in parameter Rect. I don't know how I can deadlier it?

推荐答案

接受两个cv::Point的cv::rectangle函数采用矩形的左上角和右下角(分别位于矩形中的pt1和pt2 文档).如果该矩形与接受cv::Rect的cv::rectangle函数一起使用，那么您将获得相同的结果.

The cv::rectangle function that accepts two cv::Point's takes both the top left and the bottom right corner of a rectangle (pt1 and pt2 respectively in the documentation). If that rectangle is used with the cv::rectangle function that accepts a cv::Rect, then you will get the same result.

// just some valid rectangle arguments
int x = 0;
int y = 0;
int width = 10;
int height = 20;
// our rectangle...
cv::Rect rect(x, y, width, height);
// and its top left corner...
cv::Point pt1(x, y);
// and its bottom right corner.
cv::Point pt2(x + width, y + height);
// These two calls...
cv::rectangle(img, pt1, pt2, cv::Scalar(0, 255, 0));
// essentially do the same thing
cv::rectangle(img, rect, cv::Scalar(0, 255, 0))

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