为什么openssl/ssl.h只包含相对路径? [英] Why does openssl/ssl.h contain nothing but a relative path?

问题描述

我通过执行以下操作，使用MSVC ++ 2013 Express编译器构建了OpenSSL:

I built OpenSSL using the MSVC++ 2013 Express compiler by doing the following:

• 从 openssl-1.0.1e.tar.gz 并将其提取到C:\OpenSSL\Win64.
• 打开"VS2013 x64交叉工具命令提示符"，然后cd进入我提取存档的目录.

• 运行以下命令:

• Installing ActivePerl 5.16.3 from here.
• Grabbing openssl-1.0.1e.tar.gz and extracting it to C:\OpenSSL\Win64.
• Opening up the "VS2013 x64 Cross Tools Command Prompt" and cd-ing to the directory where I had extracted the archive.

• Running the following commands:

perl Configure VC-WIN64A
ms\do_win64a
nmake -f ms\ntdll.mak

此操作已完成，没有错误(已构建正确的DLL).但是，发生了非常奇怪的事情.如果打开openssl/ssl.h，则文件内容为:

This completed without errors (the proper DLLs are built). However, something very strange has happened. If I open up openssl/ssl.h, the contents of the file are:

../../ssl/ssl.h

由于这显然不是有效的C/C ++，由于上述问题，我无法编译任何依赖于OpenSSL标头的应用程序.我做错了什么?

Since this is obviously not valid C/C++, I can't compile any applications that depend on OpenSSL headers due to the problem above. What have I done wrong?

推荐答案

duskwuff 的 GnuWin32的tar命令行实用程序，并将其用于提取档案:

duskwuff's comment was indeed correct. The problem was that 7-Zip didn't properly extract the symbolic links in the archive. The solution was to download GnuWin32's tar command line utility and use that to extract the archive:

tar -xvf openssl-1.0.1e.tar.gz

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