如何在C ++中重载cout行为 [英] How to overload cout behaviour in c++

问题描述

我想让cout每次调用时都将始终打印其他字符串(上下).实际上，这对我来说很奇怪，因为我最初在Java和C#中使用它. 也许我们可以为"y"字符串或类似的东西定义其他值?

I would like to make cout will always print additional string(above and under) whenever I call it. It is actually weird to me cause I use in Java and C# primaly . Maybe we can define other value for "y" string or something like that?

示例

代码:

#include <iostream>
int main(){std::cout<<"y\n";}

结果(打印):

x
y
z

我不想更改int main()方法，只是想覆盖字符串类型的<<吗?

I would not want to change int main() method just maybe overriding the << for the string type?

或可能 使cout调用其他方法?

OR MAYBE make cout invoke additional method?

推荐答案

我认为您不能使用cout做到这一点.相反，您可以做的是创建一个简单的I/O包装器，进行额外的打印，然后调用cout进行实际工作.

I don't think you can do this with cout. What you can do instead is create a simple I/O wrapper that does your extra printing and then calls into cout to do the real work.

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