班级经营者 [英] Class operators

问题描述

我在编写代码时遇到问题:

I'm having a problem to make the code:

void main(){
     Matrix c(rows,cols);//rows & cols are int numbers
     c[0][0]=2//the line that I'm having a problem to do the operator
}

//My class defined like this: 
class Matrix{
public:
     Matrix(int rows,int cols): rows(rows), cols(cols){
         mat= new double*[cols];
         for( int i=0; i<rows;i++){
             *mat=new double[i];
         }
     }
private:
     int rows,cols;
     double **mat;
};

我怎样才能使一位操作员能够帮助我完成遇到问题的生产线?

How can I make an operator that will help me to do the line that I'm having a problem with?

推荐答案

没有operator [][]，但有operator[].这样一来，您应该返回也可以使用[]的内容(指针或代理类).

There are no operator [][], but operator[]. So that one should return something for which you can use [] too (pointer or proxy class).

就您而言，您可以简单地这样做:

In your case, you might simply do:

double* operator[](int i) { return mat[i]; }
const double* operator[](int i) const { return mat[i]; }

对于更复杂的情况，您必须返回一个代理类.

For more complicated cases, you have to return a proxy class.

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