重载+/-一元运算符 [英] Overloading +/- unary operators

问题描述

当重载-一元运算符时，对于不可变类型，可以这样写:

When you overload the - unary operators, for an immutable type, you can write it like:

public static Point3 operator - (Point3 p)
{
    return new Point3 (-p.X, -p.Y, -p.Z);
}

但是对于+一元运算符，您应该如何实现呢?像这样:

But for the + unary operator, how should you implement it? Like this:

public static Point3 operator + (Point3 p)
{
    return p;
}

或类似这样:

public static Point3 operator + (Point3 p)
{
    return new Point3 (p);
}

推荐答案

两种方法都可以.您不会使用这两种方法中的任何一种来对原始对象进行变异.

Either way is fine. You are not mutating the original object in either of the two methods.

如果调用string.substring(0, string.length())，则没有理由无法返回原始字符串.

If you call string.substring(0, string.length()), there is no reason why the original string cannot be returned.

您唯一签署的具有不变性的合同是，一旦创建了对象，它就不会改变.

The only contract you sign with immutability is that once an object is created, it doesn't change.

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