重载一元运算符& [英] Overloading unary operator &

问题描述

让我们考虑一个带有重载的一元运算符& （地址）。让它 A类

 模板< class C& 
 class A 
 {
 public：
 C * operator&（）
 {
 return& data; 
} 
 // ... 
 private：
 C data; 
} 
  

现在我想传递给某个函数类型 A 以填充其数据。让我们称之为 f

  void f（A * auto_containter）
 {
 // ... 
} 
  

清楚为什么代码下面将不工作（甚至不会编译）。这是因为重载的操作符被调用。

  A a; 
 f（& a）; 
  

问题如下：

有任何语法将 a 的地址传递到 f ？如果没有，那么对我来说很奇怪为什么它允许重载一元运算符& ，因为它使代码更加错误和难以理解。

使用 boost :: addressof 功能。在任何情况下，是高度怀疑。为什么不使用返回数据地址的命名函数呢？

Let's consider a class with overloaded unary operator & (Address-of). Let it be class A

template <class C>
class A
{
public:
    C * operator &()
    {
        return &data;
    }
    //...
private:
    C data;
}

Now I want to pass to some function a pointer of type A to fill its data. Let us call it f

void f(A * auto_containter)
{
    //...
}

But it is clear why the code bellow wouldn't work (even wouldn't compile). It is because the overloaded operator is called.

A a;
f(&a);

The question is following:

Is there any syntax to pass address of a to f? If no, then for me it is very strange why it is allowed to overload unary operator &, because it makes code more buggy and difficult to understand. Or there are some other reasons?

解决方案

Use boost::addressof function. In any case, overloading unary & is highly dubious. Why do it instead of having a named function that returns the address of your data?

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