如何将二进制矩阵转换为R中的data.frame? lpSolveAPI [英] How to turn a binary matrix into a data.frame in R? lpSolveAPI
问题描述
library(lpSolveAPI)
lprec1 <- make.lp(0,nrow(df)
add.constraint(lprec1, c(1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads1))
add.constraint(lprec1, c(0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads2))
add.constraint(lprec1, c(0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads3))
add.constraint(lprec1, c(0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads4))
add.constraint(lprec1, c(0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads5))
add.constraint(lprec1, c(0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads6))
add.constraint(lprec1, c(0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads7))
add.constraint(lprec1, c(0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads8))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads9))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads10))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads11))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads12))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads13))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads14))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads15))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads16))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads17))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads18))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads19))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads20))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads21))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads22))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads23))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0), "<=", as.numeric(ads24))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0), "<=", as.numeric(ads25))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0), "<=", as.numeric(ads26))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0), "<=", as.numeric(ads27))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0), "<=", as.numeric(ads28))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0), "<=", as.numeric(ads29))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0), "<=", as.numeric(ads30))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0), "<=", as.numeric(ads31))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0), "<=", as.numeric(ads32))
add.constraint(lprec1, c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1), "<=", as.numeric(ads33))
solve(lprec1)
print(get.variables(lprec1))
print(get.objective(lprec1))
我将所有 ads 向量都转换为单个data.frame df $ ads,是否也可以转换此矩阵?我尝试使用
I turned all my ads vectors into a single data.frame df$ads, is there any way to transform this matrix too? I tried using
add.constraint(lprec1, diag(nrow (df))), "<=", as.vector(df$ads))
solve(lprec1)
但是lpSolveAPI识别出长度是不同的: add.constraint(lprec1,diag(nrow(df),< =",df $ ads)中的错误: "xt"的长度不等于模型中决策变量的数量,但是有33个决策变量,nrow(df)为33 ... 有什么方法可以使矩阵二值化吗?
but lpSolveAPI recognizes that length is different:Error in add.constraint(lprec1, diag(nrow(df), "<=", df$ads) : the length of ‘xt’ is not equal to the number of decision variables in the model but there are 33 decision variables and the nrow(df) are 33... Is there any way to binarize without having to make this matrix?
length(diag(nrow(df))) = 361
长度是不同的大小,有什么方法可以将这些向量转换为一个长度为33的数据帧吗?
The length is different sizes, is there any way to turn these vectors into a single data.frame with length = 33?
推荐答案
这里是一个选项,其中我们创建向量的list
,遍历list
的序列并分配约束
Here is an option, where we create a list
of vectors, loop through the sequence of list
and assign the constraints
a <- as.vector(diag(5))
lst1 <- asplit(matrix(a, ncol = 5, byrow = TRUE), 1)
library(lpSolveAPI)
lprec1 <- make.lp(0, length(lst1))
ads <- c(0, 5, 1, -1, 0)
for(i in seq_along(lst1)) add.constraint(lprec1, lst1[[i]], "<=", ads[i])
solve(lprec1)
#[1] 2
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