Oracle SQL:使用分隔字符串对行进行排序 [英] Oracle SQL : sort row with delimited string

问题描述

我的SQL查询(在Oracle 11g中)返回这样的列:

My SQL query (in Oracle 11g) returns a column like this:

31132,11100,44232
25464,89453,15686
21561,68547,51612

我要订购这些单元格，我的意思是:

I want to order these cells, I mean:

11100,31132,44232
15686,25464,89453
21561,51612,68547

我该怎么做?

提前谢谢！

推荐答案

您可以使用REGEXP_SUBSTR从每一行中提取单个数字，然后使用LISTAGG以所需的顺序重新加入它们-类似于以下内容:

You can use REGEXP_SUBSTR to pull out the individual numbers from each row, and then use LISTAGG to rejoin them in the desired order -- something like the below:

WITH 
  T (N) AS --TEST DATA
    (SELECT '31132,11100,44232' FROM DUAL
    UNION
    SELECT '25464,89453,15686' FROM DUAL
    UNION
    SELECT '21561,68547,51612' FROM DUAL),
  T1 (N1) AS --USE THIS BELOW TO SEPARATE OUT FIRST/SECOND/THIRD VALUE FROM EACH ROW
    (SELECT 1 FROM DUAL UNION SELECT 2 FROM DUAL UNION SELECT 3 FROM DUAL),
  SEPARATED (RN,N) AS 
    (SELECT RN,REGEXP_SUBSTR(N,'[^,]+',1,T1.N1) N FROM --GET THE VALUES FROM EACH ROW WITH AN ACCOMPANYING ROW NUMBER SO WE CAN REGROUP THEM BELOW
      (SELECT ROW_NUMBER() OVER(ORDER BY 1) RN ,N FROM T),T1)
SELECT LISTAGG(N,',') WITHIN GROUP (ORDER BY N) FROM SEPARATED GROUP BY RN; --USE LISTAGG TO REJOIN THE SEPARATED VALUES IN THE DESIRED ORDER

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