C ++更新控制台输出 [英] C++ Update console output
问题描述
我正在尝试制作一个程序以打印出网格，并给出x和y坐标来更改网格中的值.例如，如果用户输入X:0和Y:0，则会将下图中的值'9'更改为预定义的值(在这种情况下，我想将值9更改为0).
I'm trying to make a program to print out a grid and given x and y co-ordinates change a value in the grid. For example, if the user entered X:0 and Y:0 it would change the value '9' in the image below to a predefined value (in this case I want to change the value 9 to 0).
我的问题是，是否可以更新控制台的输出，以使"0"将覆盖"9"，而无需再次打印出整个网格.我希望能够多次执行此操作.
My question is, is it possible to update the output of the console so that the '0' would override the '9' without printing out the entire grid again. I want to be able to do this multiple times.
如果这不可能，那么如何以实现此方式的方式打印出更新的网格?如果我将显示网格 for循环放在一个单独的函数中，则需要调用2d数组作为我确定不能执行的参数.
If that is not possible, how can I print out the updated grid the way I have implemented this? If I were to put the display grid for loop in a separate function I would need to call the 2d array as a parameter which I'm sure you cannot do.
这就是我所拥有的:
void generateGrid(int diff){
srand(time(NULL));
int arr[maximum][maximum];
for (int i=0;i<diff;i++)
{
for (int j=0;j<diff;j++)
{
arr[i][j] = rand() % 9 + 1;
}
}
cout<<"\n\tPuzzle\n\t";
for(int i=0;i<diff;i++)
{
cout<<i<<" ";
}
cout<<"\n\n";
for(int i=0;i<diff;i++)
{
cout<<i<<"\t";
for(int j=0;j<diff;j++)
{
cout<<arr[i][j]<<" ";
}
cout<<"\n";
}
int x, y;
cout<<"\nEnter x value: ";
cin>>x;
cout<<"Enter y value: ";
cin>>y;
arr[x][y] = 0;
}
差异是指拼图的大小(难度)
Diff refers to the puzzle size (difficulty)
其他地方:
int easy = 5;
int medium = 8;
int hard = 10;
int maximum = 10;
推荐答案
标准C ++不支持在控制台位置上设置单个字符，而无需重新打印.这是特定于操作系统的，并且有一些注释可以解决此问题.
Standard C++ does not support setting individual characters at positions in the console without re-printing. This is OS-specific, and there are comments that address this.
否则，正确的解决方案是将游戏板逻辑封装到一个类中.我们可以使用嵌套的std::vector来处理动态尺寸的电路板，并提供获取和设置单元格的功能.单独的Print功能使我们可以根据需要将板子打印到控制台的次数.
Otherwise, the correct solution is to encapsulate your game board logic into a class. We can use a nested std::vector to handle a dynamically-sized board, and provide functions for getting and setting cells. A separate Print function allows us to print the board to the console as often as we'd like.
class Grid
{
public:
Grid(int size) : myGrid(size, std::vector<int>(size, 0)) // initialize grid to be correctly sized and all zeros
{
Randomize();
}
void Randomize()
{
for (size_t i=0;i<myGrid.size();i++)
{
for (size_t j=0;j<myGrid[i].size();j++)
{
myGrid[i][j] = rand() % 9 + 1;
}
}
}
void Print(std::ostream& out) const
{
out<<"\n\tPuzzle\n\t";
for(size_t i=0;i<myGrid.size();i++)
{
out<<i<<" ";
}
out << "\n\n";
for(size_t i=0;i<myGrid.size();i++)
{
out<<i<<"\t";
for(size_t j=0;j<myGrid[i].size();j++)
{
out<<myGrid[i][j]<<" ";
}
out<<"\n";
}
}
int GetValue(size_t row, size_t col) const
{
// use wraparound for too-large values
// alternatively you could throw if row and/or col are too large
return myGrid[row % myGrid.size()][col % myGrid.size()];
}
void SetValue(size_t row, size_t col, int val)
{
myGrid[row % myGrid.size()][col % myGrid.size()] = val;
}
private:
std::vector<std::vector<int>> myGrid;
};
现在，您可以像这样编写main:
Now you can write your main like so:
int main()
{
srand(time(NULL));
Grid board(10);
size_t xValue = 0;
size_t yValue = 0;
// game loop. You could even abstract this behavior into another class
while(true)
{
board.Print(std::cout);
std::cout<<"\nEnter x value: ";
if (!std::cin) // check for no input
break;
std::cin>>xValue;
if (!std::cin) // check for end of input
break;
std::cout<<"Enter y value: ";
std::cin>>yValue;
if (!std::cin)
break;
board.SetValue(xValue, yValue, 0);
// other game logic...
}
// print board one last time before exit
std::cout << "Game over. Final board: \n";
board.Print(std::cout);
}
这篇关于C ++更新控制台输出的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
