写入文件+文件名是需要稍作操作的字符串 [英] Write to a file + filename is a string that needs to be manipulated slightly

问题描述

这是我要操作的字符串，并且是我要写入的文件名的一部分:

This is a string I want to manipulate and be part of a filename I want to write to:

$ echo "$val1"
"$29.95 Carryover Plan 1GB"

这就是我想要的文件名(用下划线和双引号删除的空格)，并在开始时添加了NAME_，并在末尾添加了_NAME.

This is what I want the file name to be, (spaces repalaced with underscore and double quotes removed) and NAME_ added at start and _NAME added at end.

$ echo "NAME_"$val1"_NAME" | sed s/" "/_/g | sed s/'"'/''/g
NAME_$29.95_Carryover_Plan_1GB_NAME

这是我试图将测试数据写入有问题的文件

And this is me trying to write test data to the file in question

$ a="NAME_"$val1"_NAME" | sed s/" "/_/g | sed s/'"'/''/g && echo "test123" > "$a"

但是它并没有如我所愿的出现"$29.95_Carryover_Plan_1GB"

But it does not come out as I want "$29.95_Carryover_Plan_1GB"

$ ls -lth
total 44M
-rw-r--r-- 1 kevin.smith mkpasswd    8 Jul 25 16:08 "$29.95_Carryover_Plan_1GB"

我该如何写入文件，并将文件名更改为 NAME_$29.95_Carryover_Plan_1GB_NAME?

推荐答案

a="NAME_"$val1"_NAME" | sed s/" "/_/g | sed s/'"'/''/g

不执行我期望的操作.您实际上需要echo变量:

doesn't do what I expect you wanted it to. You'll need to actually echo the variable:

a="$(echo "NAME_"$val1"_NAME" | sed s/" "/_/g | sed s/'"'/''/g)"

或者更好(IMO):

a="$(echo "NAME_${val1}_NAME" | sed 's/ /_/g;s/"//g')"

或者如果您运行的是zsh而不是bash:

Or if you're running zsh rather than bash:

a="NAME_${${val1// /_}//\"/}_NAME"

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