搜索+替换文件名中的字符串 [英] Search+replace strings in filenames

问题描述

使用bash，我如何在目录中以递归方式包含在所有文件名(包括文件夹)中搜索所有出现的子字符串"foo"，并将其替换为"bar"?

Using bash, how can I search for all occurrences of the substring 'foo' in all filenames (including folders) contained recursively in a directory and replace them them with 'bar'?

例如，如果当前结构如下:

For example, if the current structure looks like:

-foo_test
    - fooo.txt
    - xfoo
        - yfoo.h
- 1foo.c

运行bash脚本后，它应如下所示:

It should look like this after running the bash script:

-bar_test
    - baro.txt
    - xbar
        - ybar.h
- 1bar.c

推荐答案

此处显示的两种变体在OPs测试结构上均可以正常使用:

Both variations shown here using work correctly on OPs test structure:

find . -depth -name '*foo*' -execdir bash -c 'mv -i "$1" "${1//foo/bar}"' bash {} \;

或者，如果您有大量文件并希望其运行得更快:

or, if you have a very large number of files and want it to run faster:

find . -depth -name '*foo*' -execdir bash -c 'for f; do mv -i "$f" "${f//foo/bar}"; done' bash {} +

编辑:如评论中所述，我之前使用不使用execdir选项并使用rename的find命令的答案在重命名包含foo的目录中的文件时遇到问题以他们的名字.如建议的那样，我已将find命令更改为使用-execdir，并且由于它是非标准命令，因此已使用rename命令删除了变体.

EDIT: As noted in the comments, my earlier answer using a find command that did not use the execdir option and using rename has problems renaming files in directories that contain foo in their name. As suggested, I have changed the find commands to use -execdir, and I have deleted the variation using the rename command since it is a non-standard command.

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